FF:=EMA(CLOSE,3);? ?MA15:=EMA(CLOSE,21);? ?XG:=CROSS(FF,MA15);
底违背:(CROSS(C,MA(C,5))?
?AND CROSS(C,MA(C,10))
?AND CROSS(C,MA(C,20))?
?A</p>
FF:=EMA(CLOSE,3);?
?MA15:=EMA(CLOSE,21);?
?XG:=CROSS(FF,MA15);</p>
底违背:(CROSS(C,MA(C,5))?
?AND CROSS(C,MA(C,10))
?AND CROSS(C,MA(C,20))?
?AND C>O?
?AND XG);</p>